Hmmm, after thinking about it, better see
?mapply
SIMPLIFY logical; attempt to reduce the result to a vector or
matrix?
Try mapply( ..., SIMPLIFY=FALSE )
HTH,
Chuck
On Mon, 12 Oct 2009, Magnus Torfason wrote:
I have a list of isometric structures, and I want to change the same part of
each structure in the list, assigning one element of a vector to each of
these parts.
In other words, I want to achieve the following:
l <- list( list(a=1,b=2), list(a=3,b=4))
unlist(lapply(l, "[[", "a"))
[1] 1 3
# This will not actually work
l[[]]["a"] <- 5:6
unlist(lapply(l, "[[", "a"))
[1] 5 6
I figure mapply is the solution to the problem, and I tried the following:
mapply( "[<-", l, "a", 5:6)
But the result is not the same shape as the original.
Any thoughts?
Best,
Magnus
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Charles C. Berry (858) 534-2098
Dept of Family/Preventive Medicine
E mailto:cbe...@tajo.ucsd.edu UC San Diego
http://famprevmed.ucsd.edu/faculty/cberry/ La Jolla, San Diego 92093-0901
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
