Try
require(chron)
dat <- read.table(textConnection("Timestamp1 Timestamp2
05:24:43 05:25:05
15:47:02 15:47:22
18:36:05 18:36:24
15:21:24 15:22:04"), T)
closeAllConnections()
str(dat)
dat[,1] <- times(dat[,1])
dat[,2] <- times(dat[,2])
# numeric
as.numeric(dat[,2] <- times(dat[,2]) )
# test to get seconds from days
86400*as.numeric(dat[,2]-dat[,1])
You may want to check Rnews volume 4(1)
Regards
Duncan Mackay
At 09:50 3/09/2009, you wrote:
Hi all,
I have the following problem: I have a csv-file consisting of timestamp
values (no dates), e.g.:
Timestamp1;Timestamp2;
05:24:43;05:25:05;
15:47:02;15:47:22;
18:36:05;18:36:24;
15:21:24;15:22:04;
I need a vector with the difference of the two timestamps, so I read the
data with the read.csv-function:
myObj <- read.csv("file.csv",header=TRUE,sep=";").
I have then tried unsuccessfully to convert the data to time format (e.g.
using the strptime function like date1 <-
strptime(myObj[0],format="%H:%M:%S")) to be able to perform a datediff
operation.
I would be very grateful if anybody could give me some assistance.
Thanks in advance,
Ieyasu
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