Try this:
> Lines <- "Timestamp1;Timestamp2;
+ 05:24:43;05:25:05;
+ 15:47:02;15:47:22;
+ 18:36:05;18:36:24;
+ 15:21:24;15:22:04;"
>
> library(chron)
> DF <- read.csv(textConnection(Lines), sep = ";", as.is = TRUE)
> times(DF$Timestamp2) - times(DF$Timestamp1)
[1] 00:00:22 00:00:20 00:00:19 00:00:40
See the relevant article in R News 4/1 and its references for more info.
On Wed, Sep 2, 2009 at 7:50 PM, sugo<iey...@sugimoto.at> wrote:
>
> Hi all,
>
> I have the following problem: I have a csv-file consisting of timestamp
> values (no dates), e.g.:
> Timestamp1;Timestamp2;
> 05:24:43;05:25:05;
> 15:47:02;15:47:22;
> 18:36:05;18:36:24;
> 15:21:24;15:22:04;
>
> I need a vector with the difference of the two timestamps, so I read the
> data with the read.csv-function:
> myObj <- read.csv("file.csv",header=TRUE,sep=";").
>
> I have then tried unsuccessfully to convert the data to time format (e.g.
> using the strptime function like date1 <-
> strptime(myObj[0],format="%H:%M:%S")) to be able to perform a datediff
> operation.
>
> I would be very grateful if anybody could give me some assistance.
>
> Thanks in advance,
> Ieyasu
> --
> View this message in context:
> http://www.nabble.com/diff-of-two-timestamps-tp25267603p25267603.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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