That did not actually deliver the requested results because it bound
before it unique-ed.
> unique(do.call(rbind,z))
[,1] [,2]
[1,] 11 0
[2,] 9 0
[3,] 10 1
[4,] 7 1
I found it necessary to do a bit more list processing before the
rbind:
> do.call( rbind, lapply(z, function(x) x[!duplicated(x[,1]), ] ) )
[,1] [,2]
[1,] 11 0
[2,] 9 0
[3,] 10 1
[4,] 7 1
[5,] 10 1
--
David Winsemius
On Jul 28, 2009, at 6:29 PM, Jorge Ivan Velez wrote:
Dear Kathryrn,
Here is one way:
unique(do.call(rbind,z))
See ?unique, ?do.call and ?rbind for more information.
HTH,
Jorge
On Tue, Jul 28, 2009 at 6:21 PM, kathie <> wrote:
Dear R users...
I have a list, "z", below.
z<-list(matrix(c(11,11,9,0,0,0),3,2),matrix(c(10,10,10,1,1,1),3,2),
matrix(c(7,10,1,1),2,2))
z
[[1]]
[,1] [,2]
[1,] 11 0
[2,] 11 0
[3,] 9 0
[[2]]
[,1] [,2]
[1,] 10 1
[2,] 10 1
[3,] 10 1
[[3]]
[,1] [,2]
[1,] 7 1
[2,] 10 1
From the list, I need to remove duplicated rows based on the 1st
column in
each "z" element, and then eventually make one matrix as followings;
[,1] [,2]
[1,] 11 0 <---- from z[1]
[2,] 9 0 <---- from z[1]
[3,] 10 1 <---- from z[2]
[4,] 7 1 <---- from z[3]
[5,] 10 1 <---- from z[3]
Any comments will be greatly appreciated.
Regards,
Kathyrn Lord
--
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______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
