Dear Kathryrn, Here is one way: unique(do.call(rbind,z))
See ?unique, ?do.call and ?rbind for more information. HTH, Jorge On Tue, Jul 28, 2009 at 6:21 PM, kathie <> wrote: > > Dear R users... > > > I have a list, "z", below. > > > z<-list(matrix(c(11,11,9,0,0,0),3,2),matrix(c(10,10,10,1,1,1),3,2), > matrix(c(7,10,1,1),2,2)) > > > z > [[1]] > [,1] [,2] > [1,] 11 0 > [2,] 11 0 > [3,] 9 0 > > [[2]] > [,1] [,2] > [1,] 10 1 > [2,] 10 1 > [3,] 10 1 > > [[3]] > [,1] [,2] > [1,] 7 1 > [2,] 10 1 > > > >From the list, I need to remove duplicated rows based on the 1st column in > each "z" element, and then eventually make one matrix as followings; > > [,1] [,2] > [1,] 11 0 <---- from z[1] > [2,] 9 0 <---- from z[1] > [3,] 10 1 <---- from z[2] > [4,] 7 1 <---- from z[3] > [5,] 10 1 <---- from z[3] > > Any comments will be greatly appreciated. > > Regards, > > Kathyrn Lord > > > > -- > View this message in context: > http://www.nabble.com/make-one-matirx-in-list-after-removing-duplicated-rows-tp24708937p24708937.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
