On 29/07/2009, at 9:39 AM, Vivek Ayer wrote:
That just creates one object and doesn't contain any $ subobjects in
it. Here's what I did to figure it out (It's complicated):
for(i in c(1:13))
assign(paste("bc",i,sep=""),read.csv(paste
(i,".csv",sep=""),sep="",header=TRUE))
in shorthand: for {assign(paste,read(paste))}
This creates individual objects for each csv file and allows me to
have $ subjects, e.g., bc1$foo.
I don't know what you mean by ``doesn't contain any $ subobjects'',
but Steve's suggested approach is much better than yours in terms
of convenient processing of the results. It's much better, generally
speaking, to have related objects bundled together into a list, which
is what Steve's approach does, rather than to have a large number of
individual objects floating around in your work space, which is what
your method does.
I would suggest that you learn about lists and the techniques for
addressing and extracting their components. It will pay off in saving
you a great deal of time and effort in the future.
cheers,
Rolf Turner
Thanks again,
Vivek
On Tue, Jul 28, 2009 at 2:12 PM, Steve
Lianoglou<mailinglist.honey...@gmail.com> wrote:
Hi,
On Jul 28, 2009, at 4:54 PM, Vivek Ayer wrote:
Hi all,
I have 13 csv files and I want to assign each csv file to one
object,
i.e.,
bc1 <- read.csv("1.csv,header=TRUE,sep="")
bc2 <- read.csv("2.csv,header=TRUE,sep="")
bc3 ...
So I want to create 13 objects. How could I automate this with a
for loop?
for (i in c(1:13)) ...
Any ideas?
objects <- lapply(1:13, function(i) {
read.csv(paste(i, 'csv', sep='.'), header=TRUE, sep="")
})
-steve
--
Steve Lianoglou
Graduate Student: Computational Systems Biology
| Memorial Sloan-Kettering Cancer Center
| Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact
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