That just creates one object and doesn't contain any $ subobjects in
it. Here's what I did to figure it out (It's complicated):
for(i in c(1:13))
assign(paste("bc",i,sep=""),read.csv(paste(i,".csv",sep=""),sep="",header=TRUE))
in shorthand: for {assign(paste,read(paste))}
This creates individual objects for each csv file and allows me to
have $ subjects, e.g., bc1$foo.
Thanks again,
Vivek
On Tue, Jul 28, 2009 at 2:12 PM, Steve
Lianoglou<mailinglist.honey...@gmail.com> wrote:
> Hi,
>
> On Jul 28, 2009, at 4:54 PM, Vivek Ayer wrote:
>
>> Hi all,
>>
>> I have 13 csv files and I want to assign each csv file to one object,
>> i.e.,
>>
>> bc1 <- read.csv("1.csv,header=TRUE,sep="")
>> bc2 <- read.csv("2.csv,header=TRUE,sep="")
>> bc3 ...
>>
>> So I want to create 13 objects. How could I automate this with a for loop?
>>
>> for (i in c(1:13)) ...
>>
>> Any ideas?
>
>
> objects <- lapply(1:13, function(i) {
> read.csv(paste(i, 'csv', sep='.'), header=TRUE, sep="")
> })
>
> -steve
>
> --
> Steve Lianoglou
> Graduate Student: Computational Systems Biology
> | Memorial Sloan-Kettering Cancer Center
> | Weill Medical College of Cornell University
> Contact Info: http://cbio.mskcc.org/~lianos/contact
>
>
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