Assuming that there are no duplicate dates,
try this using zoo and chron:
> Lines <- "12/9/2007 0
+ 12/16/2007 1
+ 1/1/2008 2
+ 1/3/2008 3
+ 1/12/2008 4"
>
> library(zoo)
> library(chron)
> z <- read.zoo(textConnection(Lines), FUN = chron)
> z # is automatically sorted by times
12/09/07 12/16/07 01/01/08 01/03/08 01/12/08
0 1 2 3 4
> plot(z)
See R News 4/1 for more about dates and see the
3 vignettes (pdf documents) in the zoo package for
manipulating time series with zoo.
On Tue, Jul 21, 2009 at 1:16 PM, liujb<liujul...@yahoo.com> wrote:
>
> Hello,
>
> I have a set of data that has a Date column looks like this:
> 12/9/2007
> 12/16/2007
> 1/1/2008
> 1/3/2008
> 1/12/2008
> etc.
>
> I'd like the date to look something like the follow (so that I could sort by
> date easily).
> 20071209
> 20071216
> 20080101
> 20080103
> 20080112
>
> How to do it? Thank you very much
> Julia
> --
> View this message in context:
> http://www.nabble.com/how-to-transform-m-d-yyyy-to-yyyymmdd--tp24591898p24591898.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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