warmstr...@research:~$ R
> strptime("12/9/2007","%m/%d/%Y")
[1] "2007-12-09"
> format(strptime("12/9/2007","%m/%d/%Y"),"%Y%m%d")
[1] "20071209"
>On Tue, Jul 21, 2009 at 1:16 PM, liujb<liujul...@yahoo.com> wrote: > > Hello, > > I have a set of data that has a Date column looks like this: > 12/9/2007 > 12/16/2007 > 1/1/2008 > 1/3/2008 > 1/12/2008 > etc. > > I'd like the date to look something like the follow (so that I could sort by > date easily). > 20071209 > 20071216 > 20080101 > 20080103 > 20080112 > > How to do it? Thank you very much > Julia > -- > View this message in context: > http://www.nabble.com/how-to-transform-m-d-yyyy-to-yyyymmdd--tp24591898p24591898.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
