Your question is somewhat vague, there are probably an infinite number of distributions that fit your description.
Here are 2 possibilities: > tmp <- sample( c(1,30,60), 10000000, replace=TRUE, + prob=c(0.10344, 0.9-0.10344, 0.1)) > mean(tmp) [1] 30.00041 > mean(tmp>=60) [1] 0.1001004 > > tmp2 <- rgamma(10000000, shape=1.777666, scale=30/1.777666) > mean(tmp2) [1] 29.99674 > mean(tmp2>=60) [1] 0.0999903 -- Gregory (Greg) L. Snow Ph.D. Statistical Data Center Intermountain Healthcare greg.s...@imail.org 801.408.8111 > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r- > project.org] On Behalf Of David Arnold > Sent: Tuesday, June 09, 2009 11:49 PM > To: r-help@r-project.org > Subject: [R] Creating a specific skewed distribution > > All, > Can someone help me create a skewed distribution, mean = 30, with > probability of selecting a random number from the distribution greater > than or equal 60 equal to 10%? > > I need the probability density function to equal zero at zero, and > have a maximum height at or near 30. > > Is this possible? > > And if it is possible, how can I adjust the distribution so that the > probability of selecting a random number greater than or equal to 60 > is p. > > Thanks. No idea how to start. > > David > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
