With skewed unimodal distributions, the mode can't equal the mean, so assuming you want the mean to be around 30, I find that a weibull function can get close to what you want:
> mean(rweibull(1e5,1.5,33)) [1] 29.77781 > pweibull(60,1.5,33) [1] 0.9138475 I'm sure you can play with the parameters to try to get even closer to what you want. On Wed, Jun 10, 2009 at 2:48 AM, David Arnold<dwarnol...@suddenlink.net> wrote: > All, > Can someone help me create a skewed distribution, mean = 30, with > probability of selecting a random number from the distribution greater > than or equal 60 equal to 10%? > > I need the probability density function to equal zero at zero, and > have a maximum height at or near 30. > > Is this possible? > > And if it is possible, how can I adjust the distribution so that the > probability of selecting a random number greater than or equal to 60 > is p. > > Thanks. No idea how to start. > > David > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Mike Lawrence Graduate Student Department of Psychology Dalhousie University Looking to arrange a meeting? Check my public calendar: http://tr.im/mikes_public_calendar ~ Certainty is folly... I think. ~ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
