Hi, I've realised (as I'm sure have lots of others) that the second part of my answer is complete rubbish. Obviously having a bad day.
However you could work out one over your expression which then you split into two parts, calculate and then reinvert. Apologies for version 1 David -------------------------- David Jessop Global Head of Quantitative Research UBS Investment Research +44 20 7567 9882 ----- Original Message ----- From: Jessop, David To: r-help@r-project.org <r-help@r-project.org> Cc: 840...@gmail.com <840...@gmail.com> Sent: Wed Feb 11 13:55:14 2009 Subject: How to handle large numbers? Hi In answer to your first question is that it can be anything. If we look at 0 * a = 0 and let a tend to infinity, and b * Inf = Inf and let b tend to zero then you can get both zero and infinity as an answer. If you say consider c * 1/c = 1 and let c tend to infinity then it can be one too (you get the idea). On your second point, then a bit of transformation would help: exp (a) / (exp (b) + c) = exp (a) / (exp (b) + exp (log (c)) = exp (a - (b + log (c)) For example, > exp (10) / (exp (11) - 2) [1] 0.3678917 > exp (10 - 11 - log(2)) [1] 0.1839397 So in your case you get exp (1000 - 1007 - log(5)) [1] 0.0001823764 Regards, David ------------------------------ Message: 4 Date: Wed, 11 Feb 2009 11:40:14 +0100 From: Feng Li <840...@gmail.com> Subject: [R] How to handle large numbers? To: r-help@r-project.org Message-ID: <339934530902110240y1cf64fd6u2101c3a706e1d...@mail.gmail.com> Content-Type: text/plain Dear R, I have two questions: 1, Why both R and Matlab give 0*Inf==NaN? To my knowledge, it should be zero mathematically. Am I right? 2, I need to calculate e.g. exp(a)/(exp(b)+c), where both a and b are very large numbers (>>1000, e.g a=1000, b=1007, and c=5). R gives me NaN when I use the following command: > exp(1000)/(exp(1007)+5) [1] NaN I am pretty sure this should be close to zero. My question is whether there is a general way to solve this kind of question or should I do some settings before computing? Thanks in advance! Feng
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