On Wed, 11 Feb 2009, Feng Li wrote:
1, Why both R and Matlab give 0*Inf==NaN? To my knowledge, it should be zero
mathematically. Am I right?
No. 0*Inf is NaN according to the floating point arithmetic standards that R
depends on.
It's true that 0*x==0 for all finite x, but it's also true that x*Inf==Inf for
all non-zero x, and you can't preserve both of these with 0*Inf.
2, I need to calculate e.g. exp(a)/(exp(b)+c), where both a and b are very
large numbers (>>1000, e.g a=1000, b=1007, and c=5). R gives me NaN when I
use the following command:
exp(1000)/(exp(1007)+5)
[1] NaN
I am pretty sure this should be close to zero.
No. It should be close to 1. Try 1000/(1000+5) for a simpler example.
My question is whether there
is a general way to solve this kind of question or should I do some settings
before computing?
exp(1000)/(exp(1007)+5) is 1/(exp(7)+5*exp(-1000)), which is the same as
1/exp(7) to more than 400 digits accuracy.
-thomas
Thomas Lumley Assoc. Professor, Biostatistics
tlum...@u.washington.edu University of Washington, Seattle
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