Try this:
with(d.f,
{merge(data.frame(house = rep(unique(house), each =
length(unique(pet))),
pet = unique(pet)), d.f, by = c("house", "pet"), all = TRUE)
}
)
On Thu, Dec 18, 2008 at 8:58 AM, Simon Pickett <simon.pick...@bto.org>wrote:
> Hi all,
>
> Suppose I had the below example where a survey was carried out recording
> the number of each type of pet in each house
>
> count<-c(2,1,2,1,2,3,4)
> house<-c("house1","house1","house2","house3","house4","house4","house4")
> pet<-c("dogs","cats","dogs","dogs","budgie","cat","hamster")
> d.f<-data.frame(house,pet,count)
>
> How would I acheive a dataframe that had every instance of house in column
> 1, all possible pets in column 2 and counts in column 3 like this...
>
> newhouse<-rep(unique(house),1,each=4)
> newpets<-rep(unique(pet),4)
> newcount<-c(2,1,0,0,2,0,0,0,1,0,0,0,0,3,2,4)
> newdf<-data.frame(newhouse,newpets,newcount)
>
> Is there a way of doing this without creating a new matrix and using
> programming loops?
>
> Thanks in advance, Simon.
>
>
>
> [[alternative HTML version deleted]]
>
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>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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