Try this:
as.data.frame(xtabs(count ~., d.f))
On Thu, Dec 18, 2008 at 6:25 AM, Henrique Dallazuanna <www...@gmail.com> wrote:
> Try this:
>
> with(d.f,
> {merge(data.frame(house = rep(unique(house), each =
> length(unique(pet))),
> pet = unique(pet)), d.f, by = c("house", "pet"), all = TRUE)
> }
> )
>
> On Thu, Dec 18, 2008 at 8:58 AM, Simon Pickett <simon.pick...@bto.org>wrote:
>
>> Hi all,
>>
>> Suppose I had the below example where a survey was carried out recording
>> the number of each type of pet in each house
>>
>> count<-c(2,1,2,1,2,3,4)
>> house<-c("house1","house1","house2","house3","house4","house4","house4")
>> pet<-c("dogs","cats","dogs","dogs","budgie","cat","hamster")
>> d.f<-data.frame(house,pet,count)
>>
>> How would I acheive a dataframe that had every instance of house in column
>> 1, all possible pets in column 2 and counts in column 3 like this...
>>
>> newhouse<-rep(unique(house),1,each=4)
>> newpets<-rep(unique(pet),4)
>> newcount<-c(2,1,0,0,2,0,0,0,1,0,0,0,0,3,2,4)
>> newdf<-data.frame(newhouse,newpets,newcount)
>>
>> Is there a way of doing this without creating a new matrix and using
>> programming loops?
>>
>> Thanks in advance, Simon.
>>
>>
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
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>>
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>
> [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
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