Try abs(outer(xk,x,"-"))
(see ?outer) --- On Wed, 30/7/08, dxc13 <[EMAIL PROTECTED]> wrote: > From: dxc13 <[EMAIL PROTECTED]> > Subject: [R] finding a faster way to do an iterative computation > To: r-help@r-project.org > Received: Wednesday, 30 July, 2008, 4:12 AM > useR's, > > I am trying trying to find out if there is a faster way to > do a certain > computation. I have successfully used FOR loops and the > apply function to > do this, but it can take some time to fully compute, but I > was wondering if > anyone may know of a different function or way to do this: > > x > [1] 1 2 3 4 5 > > xk > [1] 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0 > > I want to do: abs(x-xk[i]) where i = 1 to length(xk)=13. > It should result > in a 13 by 5 matrix or data frame. Does anyone have a > "quicker" solution > than FOR loops or apply()? > > Much appreciation and thanks, > dxc13 > -- > View this message in context: > http://www.nabble.com/finding-a-faster-way-to-do-an-iterative-computation-tp18718233p18718233.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
