matrix(rep(x, each=13) - xk, nrow=13) > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of dxc13 > Sent: Tuesday, July 29, 2008 2:13 PM > To: r-help@r-project.org > Subject: [R] finding a faster way to do an iterative computation > > > useR's, > > I am trying trying to find out if there is a faster way to do > a certain computation. I have successfully used FOR loops > and the apply function to do this, but it can take some time > to fully compute, but I was wondering if anyone may know of a > different function or way to do this: > > x > [1] 1 2 3 4 5 > > xk > [1] 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0 > > I want to do: abs(x-xk[i]) where i = 1 to length(xk)=13. It > should result in a 13 by 5 matrix or data frame. Does anyone > have a "quicker" solution than FOR loops or apply()? > > Much appreciation and thanks, > dxc13 > -- > View this message in context: > http://www.nabble.com/finding-a-faster-way-to-do-an-iterative- > computation-tp18718233p18718233.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > >
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
