Hello,
You don't need a loop, the R way is a vectorized solution and it's also
clearer.
Create a logical index (note only one &) and assign b, c, d where it's TRUE.
i <- try$a != "Positive" & try$a != "VUS"
try <- within(try, {
b[i] <- ''
c[i] <- ''
d[i] <- ''
})
Hope this helps,
Rui Barradas
Às 17:28 de 30/05/21, Kai Yang via R-help escreveu:
Hello List,I have a data frame which having the character columns:
| a1 | b1 | c1 | d1 |
| a2 | b2 | c2 | d2 |
| a3 | b3 | c3 | d3 |
| a4 | b4 | c4 | d4 |
| a5 | b5 | c5 | d5 |
I need to do: if a1 not = "Positive" and not = "VUS" then values of b1, c1 and
d1 will be zero out. And do the same thing for the a2 to a5 series.
I write the code below to do this. But it doesn't work. Would you please
correct my code?
Thank you,
Kai
for (i in 1:5)
{
if (isTRUE(try$a[i] != "Positive" && try$a[i] != "VUS"))
{
try$b[i]== ''
try$c[i] == ''
try$d[i]== ''
}
}
[[alternative HTML version deleted]]
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