Kai,
You have made a simple mistake. And now you cannot see it. I believe this is
not uncommon among programmers. It has happened to me more times than I want
to recall.
> On May 30, 2021, at 9:28 AM, Kai Yang via R-help <r-help@r-project.org> wrote:
>
> Hello List,I have a data frame which having the character columns:
>
> | a1 | b1 | c1 | d1 |
> | a2 | b2 | c2 | d2 |
> | a3 | b3 | c3 | d3 |
> | a4 | b4 | c4 | d4 |
> | a5 | b5 | c5 | d5 |
>
>
>
> I need to do: if a1 not = "Positive" and not = "VUS" then values of b1, c1
> and d1 will be zero out. And do the same thing for the a2 to a5 series.
> I write the code below to do this. But it doesn't work. Would you please
> correct my code?
> Thank you,
> Kai
>
>
> for (i in 1:5)
> {
> if (isTRUE(try$a[i] != "Positive" && try$a[i] != "VUS"))
> {
> try$b[i]== ''
What is the above line intended to do?
I think you need to read the line out loud stating the effect of each operator.
If you still do not see what gives, copy and paste each line to the R prompt
after the loop has run (i.e. with `i' having value 5) paying attention to any
results that are printed out.
> try$c[i] == ''
> try$d[i]== ''
> }
> }
>
>
> [[alternative HTML version deleted]]
>
HTH,
Chuck
p.s. It is highly recommended to use `<-' as the assignment operator.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
