Hello,
If you want to loop through the columns of a data.frame you can do
for(i in names(df)){
[code]
}
Another way would be
lapply(names(df), function(somecol) class(df[[somecol]]))
where class(df[[somecol]]) is just an example, you would use whatever
fits your needs.
When you say that the column in question holds "levels" do you mean it's
a factor? (factors are R's categorical variables.)
Hope this helps,
Rui Barradas
Em 06-11-2017 19:26, Matti Viljamaa escreveu:
It’s sometimes faster to ask from someone who has already learnt the syntax.
In this case one has to do e.g.
names(data$somecol)
To get the collection and then iteration through it is almost like in Python:
for(i in names(data$somecol)) {
# do something
}
Bert Gunter <bgunter.4...@gmail.com> kirjoitti 6.11.2017 kello 19.55:
Time to go through a tutorial or two! -- This forum cannot replace such self
study.
Your query evidences some basic confusion, but ?tapply or the equivalent
lapply(split(...)) construct are most likely relevant.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and sticking
things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Nov 6, 2017 at 9:40 AM, mviljamaa <mvilja...@kapsi.fi
<mailto:mvilja...@kapsi.fi>> wrote:
How can I do a for loop that does to a data.frame column what:
for x in xs:
does in Python?
Obviously the data.frame column in question holds "levels". What if the
data.frame is in matrix form?
BR, Matti
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