Except that syntax is wrong:
> d <- data.frame (a = 1:3, b = letters[1:3])
> names(d$a)
NULL
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Nov 6, 2017 at 11:26 AM, Matti Viljamaa <mvilja...@kapsi.fi> wrote:
> It’s sometimes faster to ask from someone who has already learnt the
> syntax.
> In this case one has to do e.g.
>
> names(data$somecol)
>
> To get the collection and then iteration through it is almost like in
> Python:
>
> for(i in names(data$somecol)) {
> # do something
> }
>
> Bert Gunter <bgunter.4...@gmail.com> kirjoitti 6.11.2017 kello 19.55:
>
> Time to go through a tutorial or two! -- This forum cannot replace such
> self study.
>
> Your query evidences some basic confusion, but ?tapply or the equivalent
> lapply(split(...)) construct are most likely relevant.
>
> Cheers,
> Bert
>
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along and
> sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
> On Mon, Nov 6, 2017 at 9:40 AM, mviljamaa <mvilja...@kapsi.fi> wrote:
>
>> How can I do a for loop that does to a data.frame column what:
>>
>> for x in xs:
>>
>> does in Python?
>>
>> Obviously the data.frame column in question holds "levels". What if the
>> data.frame is in matrix form?
>>
>> BR, Matti
>>
>> ______________________________________________
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>> PLEASE do read the posting guide http://www.R-project.org/posti
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>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
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