Write a for-loop that tests your condition and carries the necessary parameters
forward. break() when your condition is met.
B.
> On Oct 29, 2017, at 10:24 PM, li li <hannah....@gmail.com> wrote:
>
> Dear all,
> The function f() below is a function of m1 and m2, both of which are
> matrices with 3 rows. The function works sequentially one row after
> another.
> So altogether there are three stages. I am trying to update the coding to
> write a generic function that will work for arbitrary k stages.
> I am hoping to get some suggestion and help. Thanks so much!
> Hanna
>
>
>
>
> ##x, y are two vectors of the same length
> f0 <- function(x, y){
> I <- which((x-y)^2>0.5)
> if (length(I)==0){
> a <- 0; b <-0; c<- 0
> } else {
> a <- min(I)
> b <- x[a]
> c <- y[a]}
> return(list(a=a, b=b, c=c))
> }
>
> ##both m1 and m2 are matrix with 3 rows and same number of columns
> f <- function(m1, m2){
> n <- dim(m1)[2]
> tmp1 <- f0(m1[1,], m2[1,])
> S2 <- which(m1[1,] > tmp1$a)
> if (length(S2) == 0){
> t1 <- c(tmp1$b, 0, 0)
> t2 <- c(tmp1$c, 0, 0)} else {
> tmp2 <- f0(m1[2,S2], m2[2, (n-length(S2)+1):n])
> S3 <- S2[which(m2[2, S2] > tmp2$a)]
> if (length(S3) == 0) {
> t1 <- c(tmp1$b, tmp2$b, 0)
> t2 <- c(tmp1$c, tmp2$c, 0)} else {
> tmp3 <- f0(m1[3,S3], m2[3, (n-length(S3)+1):n])
> t1 <- c(tmp1$b, tmp2$b, tmp3$c)
> t2 <- c(tmp1$c, tmp2$c, tmp3$b)
> }}
> return(list(t1=t1, t2=t2))
> }
>
> [[alternative HTML version deleted]]
>
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