Dear all,
The function f() below is a function of m1 and m2, both of which are
matrices with 3 rows. The function works sequentially one row after
another.
So altogether there are three stages. I am trying to update the coding to
write a generic function that will work for arbitrary k stages.
I am hoping to get some suggestion and help. Thanks so much!
Hanna
##x, y are two vectors of the same length
f0 <- function(x, y){
I <- which((x-y)^2>0.5)
if (length(I)==0){
a <- 0; b <-0; c<- 0
} else {
a <- min(I)
b <- x[a]
c <- y[a]}
return(list(a=a, b=b, c=c))
}
##both m1 and m2 are matrix with 3 rows and same number of columns
f <- function(m1, m2){
n <- dim(m1)[2]
tmp1 <- f0(m1[1,], m2[1,])
S2 <- which(m1[1,] > tmp1$a)
if (length(S2) == 0){
t1 <- c(tmp1$b, 0, 0)
t2 <- c(tmp1$c, 0, 0)} else {
tmp2 <- f0(m1[2,S2], m2[2, (n-length(S2)+1):n])
S3 <- S2[which(m2[2, S2] > tmp2$a)]
if (length(S3) == 0) {
t1 <- c(tmp1$b, tmp2$b, 0)
t2 <- c(tmp1$c, tmp2$c, 0)} else {
tmp3 <- f0(m1[3,S3], m2[3, (n-length(S3)+1):n])
t1 <- c(tmp1$b, tmp2$b, tmp3$c)
t2 <- c(tmp1$c, tmp2$c, tmp3$b)
}}
return(list(t1=t1, t2=t2))
}
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