Hello,

I have never used plm but the standard way of adding a quadratic term is

I(time(year)^2)

Hope this helps,

Rui Barradas

Em 12-05-2017 15:40, Tobias Christoph escreveu:
Hey guys,

thanks a lot for your tips. The regression is finally running. As you
said, I had to integrate the column "year" in the function "time" in R.

So I used the following formula: *plm(log(revenue) ~ log(supply) +
factor(town)*time(year), data=R_Test_log_Neu)*

So I have now sucessfully added a linear trend to my regression model?
Another question that concernes me is how to add a quadratic trend
instead of a linear trend. Can I just square the column "year"?

Enjoy your weekend,

Toby

_My results see below:_

Balanced Panel: n=11, T=12, N=132

Residuals :
     Min.  1st Qu.   Median  3rd Qu.     Max.
-0.09610 -0.02370 -0.00152  0.01980  0.14000

Coefficients :
                             Estimate Std. Error t-value  Pr(>|t|)
log(supply)               -0.0080702  0.0133675 -0.6037  0.547411
factor(town)2:time(year)  -0.0063245  0.0053744 -1.1768  0.242100
factor(town)3:time(year)   0.0295522  0.0056776  5.2050 1.053e-06 ***
factor(town)4:time(year)   0.0062191  0.0054152  1.1485  0.253549
factor(town)5:time(year)   0.0159028  0.0054954  2.8939  0.004681 **
factor(town)6:time(year)   0.0237112  0.0055395  4.2804 4.316e-05 ***
factor(town)7:time(year)   0.0410007  0.0055734  7.3565 5.576e-11 ***
factor(town)8:time(year)   0.0239085  0.0053751  4.4480 2.271e-05 ***
factor(town)9:time(year)   0.0242342  0.0056855  4.2625 4.619e-05 ***
factor(town)10:time(year)  0.0105890  0.0053302  1.9866  0.049733 *
factor(town)11:time(year)  0.0095270  0.0056354  1.6906  0.094065 .
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Total Sum of Squares:    0.46388
Residual Sum of Squares: 0.2001
R-Squared:      0.56863
Adj. R-Squared: 0.4292
F-statistic: 11.8637 on 11 and 99 DF, p-value: 7.3065e-14



Am 11.05.2017 um 23:17 schrieb David L Carlson:
What Rui said, but as important, you have four columns in your data called "town", "year", 
"revenue", and "supply". You do not have a column called "time".

-------------------------------------
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352

-----Original Message-----
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Rui Barradas
Sent: Thursday, May 11, 2017 3:36 PM
To: Tobias Christoph<s3toc...@uni-bayreuth.de>; Duncan 
Murdoch<murdoch.dun...@gmail.com>;r-help@r-project.org
Subject: Re: [R] Error: invalid type (closure) for the variable 'time' - object 
specific trend

Hello,

A closure is, like you say, a function.
At an R prompt try:

  > typeof(time)
[1] "closure"

So like Duncan suggested rename 'time', for instance capitalize it
'Time'. That should do it.

Hope this helps,

Rui Barradas



Em 11-05-2017 21:20, Tobias Christoph escreveu:
Hey Duncan,

thank you very much for your quick reply.

_My data used:_

1st column(town):1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,...........,11

2nd column(year):1,2,3,4,5,6,7,8,9,10,11,12,1,2,3.......,12

3rd column (revenue):

4th colum (supply):

I have now renamed my colums and did the regression again. Now there is
a problem with R-squared, as it is the sum of 1 now with no given std.
error and t-value. This is probably due to the fact, that I try to
estimate more parameters than data.

To add a linear trend I found the following formular:*lm(y ~ x1 +
factor(ccode)*time, data=df)*

I try to I decode it for and use it for my regression: *plm(log(revenue)
~ log(supply) + factor(town)*time, data=R_Test_log_Neu)*

When I do this regression I will get the original error: "invalid type
(closure) for the variable 'time' - object specific trend"

With the notation"time" not my colum is meant, but probably the command
"time" in R.

Can you follow my thoughts?

Tobi






Am 11.05.2017 um 17:23 schrieb Duncan Murdoch:
Duncan Murdoch
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