on 06/25/2008 11:44 AM Gabor Csardi wrote:
I'm sorry to say, but this one is wrong, too.
Maybe coffee really helps, I just had one. :)
Vec <- c(20:30,20)
which(table(Vec) == 1)
21 22 23 24 25 26 27 28 29 30
2 3 4 5 6 7 8 9 10 11
You would actually need the names, but that would involve
some numberic -> character -> numeric conversion.
My previous solution is better in this respect.
Btw. to get rid of names 'unname' is better, the code is
more readable.
Best,
Gabor
OK....forget the coffee....I'm just going back to bed. :-)
The movie 'Ground Hog Day' comes to mind...
Wow. My bad.
Thanks,
Marc
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