I'm sorry to say, but this one is wrong, too. Maybe coffee really helps, I just had one. :)
> Vec <- c(20:30,20) > which(table(Vec) == 1) 21 22 23 24 25 26 27 28 29 30 2 3 4 5 6 7 8 9 10 11 You would actually need the names, but that would involve some numberic -> character -> numeric conversion. My previous solution is better in this respect. Btw. to get rid of names 'unname' is better, the code is more readable. Best, Gabor On Wed, Jun 25, 2008 at 11:37:12AM -0500, Marc Schwartz wrote: > on 06/25/2008 11:29 AM Marc Schwartz wrote: >> on 06/25/2008 11:19 AM Daren Tan wrote: >>> >>> unique(c(1:10,1)) gives 1:10 (i.e. unique values), is there any >>> method to get only 2:10 (i.e. values that are unique) ? >>> >> >> The easiest might be: >> >> > Vec >> [1] 1 2 3 4 5 6 7 8 9 10 1 >> >> > Vec[table(Vec) == 1] >> [1] 2 3 4 5 6 7 8 9 10 >> > > Correction! > > That should be: > > > which(table(Vec) == 1) > 2 3 4 5 6 7 8 9 10 > 2 3 4 5 6 7 8 9 10 > > or if you don't want a named vector: > > > as.vector(which(table(Vec) == 1)) > [1] 2 3 4 5 6 7 8 9 10 > > > My initial solution was incorrect and only worked because of the > ordering of the example vector. > > Time for another cup of cawfee...Oy > > Marc > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Csardi Gabor <[EMAIL PROTECTED]> UNIL DGM ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
