Wacek Kusnierczyk wrote:
> Ken Liu wrote:
>
>> Hi,
>>
>> I don't understand why this doesn't work:
>>
>> matTest <- matrix(nrow=3, ncol=3)
>> testMove <- function(I, J){
>> for(i in 1:I){
>> for(j in 1:J){
>> matTest[i, j] <- i+j
>> }
>> }
>> }
>> testMove(2, 3)
>> matTest
>>
>> Why the elements of the matrix matTest are still NA? How could I fix it?
>>
>>
>>
>
> i'm afraid it won't work this was, because the assignment is done on a
> copy of matTest local to the function.
> here's a simpler example:
>
> x=1
> (function() x=2)()
> # x is still 1
>
> you can fix your code with 'assign':
>
> sumfill = function(I,J) { for (i in 1:I) for (j in 1:J)
> matTest[i,j]=i+j; assign("matTest", matTest, parent.frame()) }
> sumfill(3,3)
> # matTest is filled
>
> a generic version of sumfill, if that's what you need, could be
> implemented as
>
> sumfill = function(m) { n=deparse(substitute(m)); d=dim(m); for (i in
> 1:d[1]) for (j in 1:d[2]) m[i,j]=i+j; assign(n,m,parent.frame()) }
>
> have fun.
>
... but the preferred style, i think, would be sth like:
sumfill = function(I,J) { m=matrix(nrow=I,ncol=J); for (i in 1:I) for
(j, 1:J) m[i,j]=i+j; m }
testMat = sumfill(3,3)
vQ
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