Ken Liu wrote:
> Hi,
>
> I don't understand why this doesn't work:
>
> matTest <- matrix(nrow=3, ncol=3)
> testMove <- function(I, J){
> for(i in 1:I){
> for(j in 1:J){
> matTest[i, j] <- i+j
> }
> }
> }
> testMove(2, 3)
> matTest
>
> Why the elements of the matrix matTest are still NA? How could I fix it?
>
>
i'm afraid it won't work this was, because the assignment is done on a
copy of matTest local to the function.
here's a simpler example:
x=1
(function() x=2)()
# x is still 1
you can fix your code with 'assign':
sumfill = function(I,J) { for (i in 1:I) for (j in 1:J)
matTest[i,j]=i+j; assign("matTest", matTest, parent.frame()) }
sumfill(3,3)
# matTest is filled
a generic version of sumfill, if that's what you need, could be
implemented as
sumfill = function(m) { n=deparse(substitute(m)); d=dim(m); for (i in
1:d[1]) for (j in 1:d[2]) m[i,j]=i+j; assign(n,m,parent.frame()) }
have fun.
vQ
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