Thanks for everyone's suggestions.
I think factor(foo, levels = unique(foo)) works best for my needs.
(By the way, I'm still trying to figure out how to use the ordered
option in factor().)
Andrew
On Wed, Jun 18, 2008 at 12:32 AM, Peter Alspach
<[EMAIL PROTECTED]> wrote:
> Andrew
>
> levels(factor(foo, levels=c('b','a')))
>
> should work. You can make foo an ordered factor too, but that is not
> necessary.
>
> HTH .......
>
> Peter Alspach
>
>
>> -----Original Message-----
>> From: [EMAIL PROTECTED]
>> [mailto:[EMAIL PROTECTED] On Behalf Of Andrew Yee
>> Sent: Wednesday, 18 June 2008 4:22 p.m.
>> To: r-help@r-project.org
>> Subject: [R] keeping original order in factor()
>>
>> Apologies for the naieveness of this question, but I'm having
>> trouble figuring out to have factor() maintain original ordering.
>>
>> For example,
>>
>> foo <- c("b","b","a","a")
>> levels(factor(foo, ordered=T)) #I'd like this to return as "b" "a"
>> #not "a" "b"
>>
>> I thought having ordered=T would do the trick.
>>
>> Thanks,
>> Andrew
>>
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