> foo <- sample(letters, 10, replace = TRUE)
> foo
[1] "i" "j" "u" "f" "a" "k" "m" "k" "i" "w"
> unique(foo)
[1] "i" "j" "u" "f" "a" "k" "m" "w"
> bar <- factor(foo, levels = unique(foo))
> bar
[1] i j u f a k m k i w
Levels: i j u f a k m w
>
Is this what you are trying to do?
HTH
Steve McKinney
-----Original Message-----
From: [EMAIL PROTECTED] on behalf of Andrew Yee
Sent: Tue 6/17/2008 9:22 PM
To: r-help@r-project.org
Subject: [R] keeping original order in factor()
Apologies for the naieveness of this question, but I'm having trouble
figuring out to have factor() maintain original ordering.
For example,
foo <- c("b","b","a","a")
levels(factor(foo, ordered=T)) #I'd like this to return as "b" "a"
#not "a" "b"
I thought having ordered=T would do the trick.
Thanks,
Andrew
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
