stefan.petersson wrote:
>
>
> ng,
>
> I have a matrix (x) with binary content. Each row of the matrix holds
> exactly one 1, and the rest of the row is zeros. The thing is that I need
> to 'collapse' the matrix to one column where each row holds the original
> column index of the 1's (y). Sometimes, the matrix is quite large, so I
> have a perfomance problem.
>
> x <- matrix(c(1,0,0, 0,0,1, 0,1,0, 0,0,1, 0,1,0, 1,0,0),ncol=3,byrow=T)
> x
> [,1] [,2] [,3]
> [1,] 1 0 0
> [2,] 0 0 1
> [3,] 0 1 0
> [4,] 0 0 1
> [5,] 0 1 0
> [6,] 1 0 0
>
> In the matrix above, on the first row, the 1 is in column 1, hence '1' on
> the first row in the matrix below. On the second row in the matrix above,
> the 1 is in column 3, hence the '3' on the second row in the matrix below.
> And so on...
>
> y
> [,1]
> [1,] 1
> [2,] 3
> [3,] 2
> [4,] 3
> [5,] 2
> [6,] 1
>
>
max.col(x)
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