you may try a matrix multiplication, which has a very high performance in R
x%*%1:ncol(x) hth. [EMAIL PROTECTED] schrieb:
ng, I have a matrix (x) with binary content. Each row of the matrix holds exactly one 1, and the rest of the row is zeros. The thing is that I need to 'collapse' the matrix to one column where each row holds the original column index of the 1's (y). Sometimes, the matrix is quite large, so I have a perfomance problem. x <- matrix(c(1,0,0, 0,0,1, 0,1,0, 0,0,1, 0,1,0, 1,0,0),ncol=3,byrow=T) x [,1] [,2] [,3] [1,] 1 0 0 [2,] 0 0 1 [3,] 0 1 0 [4,] 0 0 1 [5,] 0 1 0 [6,] 1 0 0In the matrix above, on the first row, the 1 is in column 1, hence '1' on the first row in the matrix below. On the second row in the matrix above, the 1 is in column 3, hence the '3' on the second row in the matrix below. And so on...y [,1] [1,] 1 [2,] 3 [3,] 2 [4,] 3 [5,] 2 [6,] 1 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
-- Eik Vettorazzi Institut für Medizinische Biometrie und Epidemiologie Universitätsklinikum Hamburg-Eppendorf Martinistr. 52 20246 Hamburg T ++49/40/42803-8243 F ++49/40/42803-7790 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
