On 19-11-2014, at 15:22, Ruima E. <ruimax...@gmail.com> wrote: > Hi, > > I have this: > > y = matrix(cbind(c(0, 0.5, 1),c(0, 0.5, 1)),ncol=2) > z = matrix(c(12, -6),ncol=2) > > In matlab I would do this > >> y .* x > > I would get this in matlab > >> ans > 0 -0 > 6 -3 > 12 -6 > > What is the equivalent in R? >
One way of doing this could be: y * rep(z,1,each=nrow(y)) Berend > Thanks > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
