Thank you Chel Hee. Isn't there a simpler way to do so?
On Wed, Nov 19, 2014 at 3:35 PM, Chel Hee Lee <chl...@mail.usask.ca> wrote: >> y = matrix(cbind(c(0, 0.5, 1),c(0, 0.5, 1)),ncol=2) >> z = matrix(c(12, -6),ncol=2) >> t(apply(y, 1, function(x) x*z)) > [,1] [,2] > [1,] 0 0 > [2,] 6 -3 > [3,] 12 -6 > > I hope this helps. > > Chel Hee Lee > > On 14-11-19 08:22 AM, Ruima E. wrote: >> Hi, >> >> I have this: >> >> y = matrix(cbind(c(0, 0.5, 1),c(0, 0.5, 1)),ncol=2) >> z = matrix(c(12, -6),ncol=2) >> >> In matlab I would do this >> >>> y .* x >> I would get this in matlab >> >>> ans >> 0 -0 >> 6 -3 >> 12 -6 >> >> What is the equivalent in R? >> >> Thanks >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
