Respected R veterans and experts,
I have a column representing time in a data frame in R.
when I call the str() function on the column it says something like this
>str(df2$Time)
Factor w/ 1441 levels "","00:01","00:02","00:03",..: 1086 1096 1111 and so on
The thing is I want to conver this column into string type such that if the
time is less than 12:00, it should get modified to the string "moring" , if
time is between 12:00 and 6:00 , it is "daylight" and so on.
The first step I thought was to convert this vector to time type of column
of data frame, so I used chron function.
I typed the following command,
>df2$Time<-chron(times=df2$Time,format=c('h:m'))
Error in convert.times(times., fmt) : format h:m may be incorrect
In addition: Warning message:In is.na(out$s) : is.na() applied to
non-(list or vector) of type 'NULL"
so I guessed I should have added second parameter in format so I tried the
following :
df2$Time<-chron(time=df2$Time,format=c('h:m:s'))
But still got the same error
I know this is just the first step, may be my approach too is wrong. Can
anyone suggest me how to convert these time data cells to morning, evening
, night etc.
Any help is much appreciated.
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