yes, I like this: a very elegant and neat solution (in my very umble
opinion)
sometime is so difficult to me to think of a solution in such a simple
and effective terms: less is more!
thank you
max
Il 03/10/2013 17:12, David Carlson ha scritto:
Try this
i=which(!sapply(mytest, is.null))
n=do.call(rbind, mytest[i])
mydf <- data.frame(i, n)
mydf
i n
1 1 45
2 3 18
3 5 99
-------------------------------------
David L Carlson
Associate Professor of Anthropology
Texas A&M University
College Station, TX 77840-4352
-----Original Message-----
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Massimo
Bressan
Sent: Thursday, October 3, 2013 9:42 AM
To: r-help@r-project.org
Subject: [R] storing element number of a list in a column data
frame
#let's suppose I have a list like this
mytest<-list(45, NULL, 18, NULL, 99)
#to note that this is just an amended example because in fact
#I'm dealing with a long list (more than 400 elements)
#with no evident pattern of the NULL values
#I want to end up with a data frame like the following
data.frame(i=c(1,3,5), n=c(45,18,99))
#i.e. a data frame storing in
#column i the number of corresponding element list
#column n the unique component of that element
#I've been trying with
do.call(rbind, mytest)
#or
do.call(rbind.data.frame, mytest)
#but this approach is not properly achieving the desired result
#now I'm in trouble on how to store each element number of the
list in
the first column data frame
#any help for this?
#thanks
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and provide commented, minimal, self-contained, reproducible code.
