Hi, Something like this, maybe: > mytest.df <- data.frame(i=seq_along(mytest)[!sapply(mytest, is.null)], > n=unlist(mytest)) > mytest.df i n 1 1 45 2 3 18 3 5 99
It took me a couple of tries, because I wasn't expecting unlist() to drop the NULL values: > unlist(mytest) [1] 45 18 99 Sarah On Thu, Oct 3, 2013 at 10:41 AM, Massimo Bressan <mbres...@arpa.veneto.it> wrote: > #let's suppose I have a list like this > > mytest<-list(45, NULL, 18, NULL, 99) > > #to note that this is just an amended example because in fact > > #I'm dealing with a long list (more than 400 elements) > > #with no evident pattern of the NULL values > > #I want to end up with a data frame like the following > > data.frame(i=c(1,3,5), n=c(45,18,99)) > > #i.e. a data frame storing in > > #column i the number of corresponding element list > > #column n the unique component of that element > > #I've been trying with > > do.call(rbind, mytest) > > #or > > do.call(rbind.data.frame, mytest) > > #but this approach is not properly achieving the desired result > > #now I'm in trouble on how to store each element number of the list in > the first column data frame > > #any help for this? > > #thanks > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
