On Apr 23, 2013, at 1:00 AM, David Winsemius wrote:
>
> On Apr 23, 2013, at 12:53 AM, Liviu Andronic wrote:
>
>> Dear David,
>> I'm having the exact same issue as Santosh, and looking at the fix
>> that you've provided it seems to me that results are slightly
>> different.
>>
> Reverse the order of arguemtns to `interaction`:
>
> tabular( (`p a`=interaction(a,p, drop=TRUE, sep=" ")) ~ (N = 1) + (b + c)*
> (mean+sd),data=q)
I suppose that instead of making transpositions in the word `argument`, I
should also have instead transposed the columns labels:
> tabular( (`a p`=interaction(a,p, drop=TRUE, sep=" ")) ~ (N = 1) + (b + c)*
+ (mean+sd),data=q)
b c
a p N mean sd mean sd
1 A 10 12.8 0.7888 52.1 8.020
3 A 10 14.6 3.7771 56.5 6.980
2 B 10 16.3 3.0569 54.9 8.71
>
> b c
> p a N mean sd mean sd
> 1 A 10 12.8 0.7888 52.1 8.020
> 3 A 10 14.6 3.7771 56.5 6.980
> 2 B 10 16.3 3.0569 54.9 8.711
>
>
>> with(q, levels( interaction(p,a, drop=TRUE, sep=" ") ) )
> [1] "A 1" "B 2" "A 3"
>> with(q, levels( interaction(a,p, drop=TRUE, sep=" ") ) )
> [1] "1 A" "3 A" "2 B"
>
>
> --
> David.
>>
>> On Tue, Apr 23, 2013 at 4:40 AM, David Winsemius <dwinsem...@comcast.net>
>> wrote:
>>>> b c
>>>> p a N mean sd mean sd
>>>> A 1 10 16.30 2.497 52.30 9.358
>>>> 2 0 NaN NA NaN NA
>>>> 3 10 15.60 2.716 60.30 8.001
>>>> B 1 0 NaN NA NaN NA
>>>> 2 10 15.40 2.366 57.70 10.414
>>>> 3 0 NaN NA NaN NA
>>>> All 30 15.77 2.473 56.77 9.601
>>>>
>>>> How do I remove the rows having N=0 ?
>>>> I would like the resulting table look like..
>>>> b c
>>>> p a N mean sd mean sd
>>>> A 1 10 16.30 2.497 52.30 9.358
>>>> 3 10 15.60 2.716 60.30 8.001
>>>> B 2 10 15.40 2.366 57.70 10.414
>>>> All 30 15.77 2.473 56.77 9.601
>>>
>>> Here's a bit of a hack:
>>>
>>> tabular( (`p a`=interaction(p,a, drop=TRUE, sep=" ")) ~ (N = 1) + (b + c)*
>>> (mean+sd),data=q)
>>>
>>> b c
>>> p a N mean sd mean sd
>>> A 1 10 12.8 0.7888 52.1 8.020
>>> B 2 10 16.3 3.0569 54.9 8.711
>>> A 3 10 14.6 3.7771 56.5 6.980
>>>
>> What Santosh and I would expect to get from the above is:
>> [..]
>> A 1 10 16.30 2.497 52.30 9.358
>> 3 10 15.60 2.716 60.30 8.001
>> [..]
>>
>> but what we get with your approach is:
>> [..]
>> A 1 10 12.8 0.7888 52.1 8.020
>> B 2 10 16.3 3.0569 54.9 8.711
>> [..]
>>
>> Although your approach makes things much better, can the original
>> ordering be retained?
>>
>>
>>> I have been rather hoping that Duncan Murdoch would have noticed the
>>> earlier thread, but maybe he can comment on whether there is a more direct
>>> route/
>>>
>> I hope so, too. Regards,
>> Liviu
>
> David Winsemius
> Alameda, CA, USA
>
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David Winsemius
Alameda, CA, USA
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