Dear David,
I'm having the exact same issue as Santosh, and looking at the fix
that you've provided it seems to me that results are slightly
different.
On Tue, Apr 23, 2013 at 4:40 AM, David Winsemius <dwinsem...@comcast.net> wrote:
>> b c
>> p a N mean sd mean sd
>> A 1 10 16.30 2.497 52.30 9.358
>> 2 0 NaN NA NaN NA
>> 3 10 15.60 2.716 60.30 8.001
>> B 1 0 NaN NA NaN NA
>> 2 10 15.40 2.366 57.70 10.414
>> 3 0 NaN NA NaN NA
>> All 30 15.77 2.473 56.77 9.601
>>
>> How do I remove the rows having N=0 ?
>> I would like the resulting table look like..
>> b c
>> p a N mean sd mean sd
>> A 1 10 16.30 2.497 52.30 9.358
>> 3 10 15.60 2.716 60.30 8.001
>> B 2 10 15.40 2.366 57.70 10.414
>> All 30 15.77 2.473 56.77 9.601
>
> Here's a bit of a hack:
>
> tabular( (`p a`=interaction(p,a, drop=TRUE, sep=" ")) ~ (N = 1) + (b + c)*
> (mean+sd),data=q)
>
> b c
> p a N mean sd mean sd
> A 1 10 12.8 0.7888 52.1 8.020
> B 2 10 16.3 3.0569 54.9 8.711
> A 3 10 14.6 3.7771 56.5 6.980
>
What Santosh and I would expect to get from the above is:
[..]
A 1 10 16.30 2.497 52.30 9.358
3 10 15.60 2.716 60.30 8.001
[..]
but what we get with your approach is:
[..]
A 1 10 12.8 0.7888 52.1 8.020
B 2 10 16.3 3.0569 54.9 8.711
[..]
Although your approach makes things much better, can the original
ordering be retained?
> I have been rather hoping that Duncan Murdoch would have noticed the earlier
> thread, but maybe he can comment on whether there is a more direct route/
>
I hope so, too. Regards,
Liviu
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