abind() (from package 'abind') can take a list of arrays as its first argument,
so in general, no need for do.call() with abind().
As another poster pointed out, simplify2array() can also be used; while abind()
gives more options regarding which dimension is created and how dimension names
are constructed.
> x <- list(A=cbind(X=c(a=1,b=2,c=3,d=4),Y=5:8,Z=9:12),
B=cbind(X=c(a=13,b=14,c=15,d=16),Y=17:20,Z=21:24))
$A
X Y Z
a 1 5 9
b 2 6 10
c 3 7 11
d 4 8 12
$B
X Y Z
a 13 17 21
b 14 18 22
c 15 19 23
d 16 20 24
>
> dim(abind(x, along=3))
[1] 4 3 2
> dim(abind(x, along=1.5))
[1] 4 2 3
> dim(abind(x, along=0.5))
[1] 2 4 3
> dim(abind(x, along=1, hier.names=T)) # construct rownames in a hierarchical
manner A.a, A.b, etc
[1] 8 3
> dim(abind(x, along=2, hier.names=T)) # construct colnames in a hierarchical
manner
[1] 4 6
> abind(x, along=2, hier.names=T)
A.X A.Y A.Z B.X B.Y B.Z
a 1 5 9 13 17 21
b 2 6 10 14 18 22
c 3 7 11 15 19 23
d 4 8 12 16 20 24
>
On 2/14/2013 3:53 AM, Rolf Turner wrote:
require(abind)
do.call(abind,c(my_list,list(along=0))) # Gives 2 x 4 x 5
do.call(abind,c(my_list,list(along=3))) # Gives 4 x 5 x 2
The latter seems more natural to me.
cheers,
Rolf Turner
On 02/14/2013 07:03 PM, Murat Tasan wrote:
i'm somehow embarrassed to even ask this, but is there any built-in
method for doing this:
my_list <- list()
my_list[[1]] <- matrix(1:20, ncol = 5)
my_list[[2]] <- matrix(20:1, ncol = 5)
now, knowing that these matrices are identical in dimension, i'd like
to unfold the list to a 2x4x5 (or some other permutation of the dim
sizes) array.
i know i can initialize the array, then loop through my_list to fill
the array, but somehow this seems inelegant.
i also know i can vectorize the matrices and unlist the list, then
build the array from that single vector, but this also seems inelegant
(and an easy place to introduce errors/bugs).
i can't seem to find any built-in that handles this already... but
maybe i just haven't looked hard enough :-/
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