require(abind)
do.call(abind,c(my_list,list(along=0))) # Gives 2 x 4 x 5
do.call(abind,c(my_list,list(along=3))) # Gives 4 x 5 x 2
The latter seems more natural to me.
cheers,
Rolf Turner
On 02/14/2013 07:03 PM, Murat Tasan wrote:
i'm somehow embarrassed to even ask this, but is there any built-in
method for doing this:
my_list <- list()
my_list[[1]] <- matrix(1:20, ncol = 5)
my_list[[2]] <- matrix(20:1, ncol = 5)
now, knowing that these matrices are identical in dimension, i'd like
to unfold the list to a 2x4x5 (or some other permutation of the dim
sizes) array.
i know i can initialize the array, then loop through my_list to fill
the array, but somehow this seems inelegant.
i also know i can vectorize the matrices and unlist the list, then
build the array from that single vector, but this also seems inelegant
(and an easy place to introduce errors/bugs).
i can't seem to find any built-in that handles this already... but
maybe i just haven't looked hard enough :-/
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