Arun, do you know why the first line works and the second doesn't?
newlist<-mapply(`[`,mylist,list(1,2,0),SIMPLIFY=FALSE) # it works
neededcolumns<-c(1,2,0) # it does not work
newlist<-mapply(`[`,mylist,list(neededcolumns),SIMPLIFY=FALSE)
Dimitri
On Tue, Feb 12, 2013 at 5:08 PM, arun <smartpink...@yahoo.com> wrote:
> Hi,
>
>
> mapply(`[`,mylist,list(1,2,0),SIMPLIFY=FALSE)
> #[[1]]
> # a
> #1 1
> #2 2
>
> #[[2]]
> # b
> #1 5
> #2 6
>
> #[[3]]
> #data frame with 0 columns and 2 rows
>
>
> A.K.
>
> ----- Original Message -----
> From: Dimitri Liakhovitski <dimitri.liakhovit...@gmail.com>
> To: r-help <r-help@r-project.org>
> Cc:
> Sent: Tuesday, February 12, 2013 4:33 PM
> Subject: [R] grabbing from elements of a list without a loop
>
> Hello!
>
> # I have a list with several data frames:
> mylist<-list(data.frame(a=1:2,b=2:3),
> data.frame(a=3:4,b=5:6),data.frame(a=7:8,b=9:10))
> (mylist)
>
> # I want to grab only one specific column from each list element
> neededcolumns<-c(1,2,0) # number of the column I need from each element of
> the list
>
> # Below, I am doing it using a loop:
> newlist<-NULL
> for(i in 1:length(mylist) ) {
> newlist[[i]]<-mylist[[i]] [neededcolumns[i]]
> }
> newlist<-do.call(cbind,newlist)
> (newlist)
>
> I was wondering if there is any way to avoid the loop above and make it
> faster.
> In reality, I have a much longer list, each of my data frames is much
> larger and I have to do it MANY-MANY times.
> Thanks a lot!
>
> Dimitri Liakhovitski
> gfk.com <http://marketfusionanalytics.com/>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
> and provide commented, minimal, self-contained, reproducible code.
>
>
--
Dimitri Liakhovitski
gfk.com <http://marketfusionanalytics.com/>
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