One could try using unlist(mylist, recursive=FALSE) to make a list of all the
columns
of the data.frames in mylist and subscripting from that. E.g., here is some
barely tested
code:
> nCols <- vapply(mylist, ncol, 0L)
> neededcolumns<-c(1,2,0) # I assume 0 means no column wanted from 3rd df in
list
> i <- neededcolumns + c(0, cumsum(nCols[-length(nCols)]))
> i <- i[neededcolumns>0]
> data.frame(unlist(mylist, recursive=FALSE)[i])
a b
1 1 5
2 2 6
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Bert Gunter
> Sent: Tuesday, February 12, 2013 2:53 PM
> To: Dimitri Liakhovitski
> Cc: r-help
> Subject: Re: [R] grabbing from elements of a list without a loop
>
> The answer is essentially no, a loop is required (as best I can see),
> although it can be in the form of an apply type call instead. Also,
> your code will fail with a 0 index. Something like this should work:
>
> newlist <- lapply(1:3,function(i)if(!neededcolumns[i])NULL else
> mylist[[c(i,neededcolumns[i])]])
>
> ## note the use of [[c(i,j)]] form for selecting columns as an
> element from a list of lists
>
> ## Note that your cbind call produces a matrix, not a list.
>
> -- Bert
>
>
> You might wish to check the parallel package, as this looks like the
> sort of thing parallellization could be profitably used for; but I
> have no experience to offer beyond that suggestion.
>
> -- Bert
>
> On Tue, Feb 12, 2013 at 1:33 PM, Dimitri Liakhovitski
> <dimitri.liakhovit...@gmail.com> wrote:
> > Hello!
> >
> > # I have a list with several data frames:
> > mylist<-list(data.frame(a=1:2,b=2:3),
> > data.frame(a=3:4,b=5:6),data.frame(a=7:8,b=9:10))
> > (mylist)
> >
> > # I want to grab only one specific column from each list element
> > neededcolumns<-c(1,2,0) # number of the column I need from each element of
> > the list
> >
> > # Below, I am doing it using a loop:
> > newlist<-NULL
> > for(i in 1:length(mylist) ) {
> > newlist[[i]]<-mylist[[i]] [neededcolumns[i]]
> > }
> > newlist<-do.call(cbind,newlist)
> > (newlist)
> >
> > I was wondering if there is any way to avoid the loop above and make it
> > faster.
> > In reality, I have a much longer list, each of my data frames is much
> > larger and I have to do it MANY-MANY times.
> > Thanks a lot!
> >
> > Dimitri Liakhovitski
> > gfk.com <http://marketfusionanalytics.com/>
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
>
>
> --
>
> Bert Gunter
> Genentech Nonclinical Biostatistics
>
> Internal Contact Info:
> Phone: 467-7374
> Website:
> http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-
> biostatistics/pdb-ncb-home.htm
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
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