Hello Ellison, Thanks very much!
I use the substr() and it works! Have a great day! Cheers, Rebecca -----Original Message----- From: S Ellison [mailto:s.elli...@lgcgroup.com] Sent: Wednesday, January 16, 2013 1:35 PM To: Yuan, Rebecca; R help Subject: RE: How to cut the time format short > I have a time format looks like > 31JAN2002:00:00:00.000 > How could I cut it to > 31JAN2002 You have several options depending on what form the data are in. Assuming it is character data, you could use substr: substr("31JAN2002:00:00:00.000", 1, 9) or gsub: gsub("(.{9}).+", "\\1", "31JAN2002:00:00:00.000") or you could convert to date and reprint: d <- as.Date("31JAN2002:00:00:00.000", format="%d%b%Y") format(d, "%d%b%Y") #albeit with lowecase month All of those should work on vectors. Some will work on factors but to be safe, wrap the factors in as.character() S Ellison ******************************************************************* This email and any attachments are confidential. Any use...{{dropped:7}} ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
