> I have a time format looks like
> 31JAN2002:00:00:00.000
> How could I cut it to
> 31JAN2002
You have several options depending on what form the data are in.
Assuming it is character data, you could use substr:
substr("31JAN2002:00:00:00.000", 1, 9)
or gsub:
gsub("(.{9}).+", "\\1", "31JAN2002:00:00:00.000")
or you could convert to date and reprint:
d <- as.Date("31JAN2002:00:00:00.000", format="%d%b%Y")
format(d, "%d%b%Y")
#albeit with lowecase month
All of those should work on vectors.
Some will work on factors but to be safe, wrap the factors in as.character()
S Ellison
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