Dear Arun,on having a bird eye view i came to notice that the data you are
using dont have month column at the beginning.my initial data was> res
$EE month 2005 2006 2008 20091 1 1.7360776 0.8095275
1.6369044 0.81952412 2 0.6962079 3.8510720 0.4319758 2.33044953 3
1.0423625 2.7687266 0.2904245 0.70155274 4 2.4158326 1.2315324 1.4287387
1.5701019
$WW month 2008 2009 20101 1 1.4737028 2.314878
2.6726612 2 1.6700918 2.609722 2.1124213 3 3.2387775 7.305766
6.9395364 4 6.7063592 18.745256 13.278218afterwards i used eliminated the
month column and got
$EE 2005 2006 2008 20091 1.7360776 0.8095275 1.6369044
0.81952412 0.6962079 3.8510720 0.4319758 2.33044953 1.0423625 2.7687266
0.2904245 0.70155274 2.4158326 1.2315324 1.4287387 1.5701019
$WW 2008 2009 20101 1.4737028 2.314878 2.6726612
1.6700918 2.609722 2.1124213 3.2387775 7.305766 6.9395364 6.7063592
18.745256 13.278218
now when i m aPPLYING rowMeans or colMeans, i am getting error.i m attaching
the text file for better understandging
eliza
> Date: Sun, 23 Dec 2012 17:40:15 -0800
> From: smartpink...@yahoo.com
> Subject: Re: [R] colmeans not working
> To: eliza_bo...@hotmail.com
> CC: r-help@r-project.org; bbol...@gmail.com
>
> Hi Eliza,
>
> I tried with the example you gave. Couldn't reproduce the error.
>
>
> res1<-list(read.table(text="
> 2005 2006 2008 2009
> 1.7360776 0.8095275 1.6369044 0.8195241
> 0.6962079 3.8510720 0.4319758 2.3304495
> 1.0423625 2.7687266 0.2904245 0.7015527
> 2.4158326 1.2315324 1.4287387 1.5701019
> ",sep="",header=TRUE),read.table(text="
> 2008 2009 2010
> 1.4737028 2.314878 2.672661
> 1.6700918 2.609722 2.112421
> 3.2387775 7.305766 6.939536
> 6.7063592 18.745256 13.278218
> ",sep="",header=TRUE))
> names(res1)<-c("EE","WW")
> res1<-lapply(res1,function(x) {names(x)<-gsub("X","",names(x));x})
> res1
> #$EE
> # 2005 2006 2008 2009
> #1 1.7360776 0.8095275 1.6369044 0.8195241
> #2 0.6962079 3.8510720 0.4319758 2.3304495
> #3 1.0423625 2.7687266 0.2904245 0.7015527
> #4 2.4158326 1.2315324 1.4287387 1.5701019
> #
> #$WW
> # 2008 2009 2010
> #1 1.473703 2.314878 2.672661
> #2 1.670092 2.609722 2.112421
> #3 3.238777 7.305766 6.939536
> #4 6.706359 18.745256 13.278218
> lapply(res1,colMeans)
> #$EE
> # 2005 2006 2008 2009
> #1.4726202 2.1652146 0.9470108 1.3554070
> #
> #$WW
> # 2008 2009 2010
> #3.272233 7.743906 6.250709
>
> lapply(res1,rowMeans)
> #$EE
> #[1] 1.250508 1.827426 1.200767 1.661551
> #
> #$WW
> #[1] 2.153747 2.130745 5.828026 12.909944
>
>
> A.K.
>
>
>
> ----- Original Message -----
> From: eliza botto <eliza_bo...@hotmail.com>
> To: bbol...@gmail.com; r-h...@stat.math.ethz.ch
> Cc:
> Sent: Sunday, December 23, 2012 7:48 PM
> Subject: Re: [R] colmeans not working
>
>
> Dear Ben,Thanks for replying but its still not working.your code
> was>lapply(res,colMeans)but i want to use "res1" instead of "res". when i did
> use it, i got same error.eliza
> > To: r-h...@stat.math.ethz.ch
> > From: bbol...@gmail.com
> > Date: Mon, 24 Dec 2012 00:31:41 +0000
> > Subject: Re: [R] colmeans not working
> >
> > eliza botto <eliza_botto <at> hotmail.com> writes:
> >
> > > Dear useRs,You must all the planning for the christmas, but i am
> > > stucked in my office on the following issue i had a file containg
> > > information about station name, year, month, day, and discharge
> > > information. i opened it by using following command
> >
> > > > dat1<-read.table("EL.csv",header=TRUE, sep=",",na.strings="NA")
> >
> > You can probably use
> >
> > dat1 <- read.csv("EL.csv")
> >
> > (although you may have to double-check some of the other
> > default differences between read.csv and read.table, e.g.
> > quote and comment.char arguments)
> >
> > > then by using following codes suggested by arun and rui i managed to
> > > obtain an
> > output
> >
> > library(reshape2)
> > res <- lapply(split(dat1,dat1$st),
> > function(x) dcast(x,month~year,mean,value.var="discharge"))
> >
> > [snip]
> >
> > res1 <- lapply(res, function(x)x[,-1])
> >
> > (c() is redundant here)
> >
> > > $EE
> > > 2005 2006 2008 2009
> > > 1 1.7360776 0.8095275 1.6369044 0.8195241
> > > 2 0.6962079 3.8510720 0.4319758 2.3304495
> > > 3 1.0423625 2.7687266 0.2904245 0.7015527
> > > 4 2.4158326 1.2315324 1.4287387 1.5701019
> > >
> > > $WW
> > > 2008 2009 2010
> > > 1 1.4737028 2.314878 2.672661
> > > 2 1.6700918 2.609722 2.112421
> > > 3 3.2387775 7.305766 6.939536
> > > 4 6.7063592 18.745256 13.278218
> > >
> > >
> >
> > Now you just need
> >
> > lapply(res,colMeans)
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
Dear arun,
> dat1<-read.table("EL.csv",header=TRUE, sep=",",na.strings="NA")
library(reshape2)
res<-lapply(split(dat1,dat1$st),function(x)
dcast(x,month~year,mean,value.var="discharge"))
> res
$EE
month 2005 2006 2008 2009
1 1 1.7360776 0.8095275 1.6369044 0.8195241
2 2 0.6962079 3.8510720 0.4319758 2.3304495
3 3 1.0423625 2.7687266 0.2904245 0.7015527
4 4 2.4158326 1.2315324 1.4287387 1.5701019
$WW
month 2008 2009 2010
1 1 1.4737028 2.314878 2.672661
2 2 1.6700918 2.609722 2.112421
3 3 3.2387775 7.305766 6.939536
4 4 6.7063592 18.745256 13.278218
i then eliminated the first column as i was interested in knowing the row wise
mean of each sublist, by using
res1 <- lapply(res, function(x)x[,1 ])
$EE
2005 2006 2008 2009
1 1.7360776 0.8095275 1.6369044 0.8195241
2 0.6962079 3.8510720 0.4319758 2.3304495
3 1.0423625 2.7687266 0.2904245 0.7015527
4 2.4158326 1.2315324 1.4287387 1.5701019
$WW
2008 2009 2010
1 1.4737028 2.314878 2.672661
2 1.6700918 2.609722 2.112421
3 3.2387775 7.305766 6.939536
4 6.7063592 18.745256 13.278218
now when i applied the "colMeans" command i was not able to calculate the mean
as i got the following error
>'x' must be an array of at least two dimensions
i cant spot the mistake in the last 5 hours.
you help is needed
eliza ______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
