Dear Ben,Thanks for replying but its still not working.your code
was>lapply(res,colMeans)but i want to use "res1" instead of "res". when i did
use it, i got same error.eliza
> To: r-h...@stat.math.ethz.ch
> From: bbol...@gmail.com
> Date: Mon, 24 Dec 2012 00:31:41 +0000
> Subject: Re: [R] colmeans not working
>
> eliza botto <eliza_botto <at> hotmail.com> writes:
>
> > Dear useRs,You must all the planning for the christmas, but i am
> > stucked in my office on the following issue i had a file containg
> > information about station name, year, month, day, and discharge
> > information. i opened it by using following command
>
> > > dat1<-read.table("EL.csv",header=TRUE, sep=",",na.strings="NA")
>
> You can probably use
>
> dat1 <- read.csv("EL.csv")
>
> (although you may have to double-check some of the other
> default differences between read.csv and read.table, e.g.
> quote and comment.char arguments)
>
> > then by using following codes suggested by arun and rui i managed to obtain
> > an
> output
>
> library(reshape2)
> res <- lapply(split(dat1,dat1$st),
> function(x) dcast(x,month~year,mean,value.var="discharge"))
>
> [snip]
>
> res1 <- lapply(res, function(x)x[,-1])
>
> (c() is redundant here)
>
> > $EE
> > 2005 2006 2008 2009
> > 1 1.7360776 0.8095275 1.6369044 0.8195241
> > 2 0.6962079 3.8510720 0.4319758 2.3304495
> > 3 1.0423625 2.7687266 0.2904245 0.7015527
> > 4 2.4158326 1.2315324 1.4287387 1.5701019
> >
> > $WW
> > 2008 2009 2010
> > 1 1.4737028 2.314878 2.672661
> > 2 1.6700918 2.609722 2.112421
> > 3 3.2387775 7.305766 6.939536
> > 4 6.7063592 18.745256 13.278218
> >
> >
>
> Now you just need
>
> lapply(res,colMeans)
>
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