Hi, Try this: dat1<-data.frame(V1=c(-9552,0,9614,0,-9752,0,0),V2=c(9552,9653,9614,9527,9752,9883,9865),V3=c("C",0,"V",0,"C",0,0)) as.matrix(subset(dat1,V3!=0)) # V1 V2 V3 #1 "-9552" "9552" "C" #3 " 9614" "9614" "V" #5 "-9752" "9752" "C" A.K.
----- Original Message ----- From: Jose Narillos de Santos <narillosdesan...@gmail.com> To: r-help <r-help@r-project.org> Cc: Sent: Tuesday, September 18, 2012 3:08 PM Subject: [R] ommoting rows Hi I have an output data Data.csv this style: ,"V1","V2","V3" 1,"-9552","9552","C" 2,"0","9653","0" 3,"9614","9614","V" 4,"0","9527","0" 5,"-9752","9752","C" 6,"0","9883","0" 7,"0","9865","0" I want to create a new matrix ommintg all the rows where third column has 0. There is a way to do it easyly? Many thanks in advance. My final matrix will have: ,"V1","V2","V3"1,"-9552","9552","C" 3,"9614","9614","V"5,"-9752","9752","C" [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.