On Aug 3, 2012, at 2:11 PM, R. Michael Weylandt wrote:
On Fri, Aug 3, 2012 at 2:53 PM, John linux-user <johnlinuxu...@yahoo.com
> wrote:
Maybe what I previously posted was not clear enough or something
else. All vectors L1,L2.. and objects (e.g. a.list, b.list, c.list)
already exit or easily to be created in a workspace. Do not worry
about those. The key question is how to systematically append/
assign these vectors to many objects (hundreds) in a loop without
explicitly typing these object names one by one. Please refer to my
code posted below to detail my question. I really appreciate your
ideas/suggestions. John
Like David, I find this still somewhat confusing, but perhaps this
will get you started:
a3 <- 1:4
b3 <- 6
c3 <- letters
a_new_thing <- do.call(list, lapply(ls(pattern = "3"), get))
old_thing <- list("cow")
a_longer_old_thing <- c(old_thing, a_new_thing)
adapt as needed.
Heh. Users of this should realize that Michael probably did this in
clean session. If you run it with any other items in the workspace
that have "3" in their names they get wrapped up too. I had a 300
line dataframe as well as a function whose values both got gathered up.
In the case where one needed to isolate a disjoint group of items, one
might want to create an environment in which to segregate those items.
the ls function can be directed to look in only one environment.
I wondered if this were the route intended:
for( i in seq_along(ls(patt=".lst") ) ) {
assign( ls(patt=".lst")[i], # the name of the i-th ".lst"-
item
append(
sapply(ls(patt=".lst$"), get)[i], # the
original value
sapply(ls(patt="^L\\d"), get)[i] ) )} # the
appended i-th "L"-value
I think it is far from optimal to have a loose collection of objects
in the workspace. Much better to have them all in one list or an
environment.
--
David Winsemius, MD
Alameda, CA, USA
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