On Aug 3, 2012, at 8:19 AM, John linux-user wrote:
Hi David,
Thanks for response, but my key question still remains unsolved.
That is, how to add many vectors (L1,L2,L3....) to many list objects
(a.list, b.list....) in a workspace?
listObjects=ls(pattern=".list") #for example, a.list, b.list...
for (object in listObjects){
#how to sign vectors L1,L2,..Ln to each object (a.list, b.list...)
}
Any suggestions/comments/ideas will be appreciated.
Can we have code that creates these entities in the workspace? (That
is what is meant as a reproducible example.) I cannot tell whether
there are already objects named "L1", "L2",... to which you wish to
append the value of the objects found, or that you want to assign
values to names that only exist as character vectors.
--
David.
John
From: David Winsemius <dwinsem...@comcast.net>
To: John linux-user <johnlinuxu...@yahoo.com>
Cc: "r-help@r-project.org" <r-help@r-project.org>
Sent: Wednesday, August 1, 2012 7:21 PM
Subject: Re: [R] add vectors to multiple objects
On Aug 1, 2012, at 8:11 AM, John linux-user wrote:
> Hi everyone,
>
> I try to add many vectors (L1,L2,L3....) to many list objects
(a.list, b.list....) in a workspace. Somethings like below, but it
is not working. Any suggestions will be appreciated. Best, John
>
> lf=ls(pattern=".lst")
>
> for (x in listfiles) {
> dat=read.delim(x,header=F)
Presumably that would fail since 'listfiles' has not been defined.
did you mean 'lf'? If you did,then wouldn't the second line
overwrite all the early values of "dat" leaving only the last one?
Perhaps:
datfils <- list()
for (x in listfiles) {
datfils[x] <- read.delim(x,header=F)
>
> for (i in 1: lf) {
And that would fail because 'lf' is a character vector, and it's not
meaningful to specify such a range. Try instead:
for (i in names(datfils[x]) ) {
#
# which will then iterate over the names of the files which are now
also the names of the list elements
> assign(i$add,as.numeric(dat[,3]))
But since 'i' is a length-1 character vector, the expression `i$add`
will be meaningless. The "$" operator does not do function calling
in R unless you do fancy things with environments, and you cannot
"sub-assign" in that manner, at least not with the assign() function.
Try instead:
assign(i, as.numeric(datfils[x][,3]))
names(i)[length(i)] <- "add"
Or:
i <- transform(i, add=datfils[x][,3] )
> #or i$add=as.numeric(dat[,3]
> names(i)[names(i)=="add"]=substr(x,1,5)
I'm not sure these would be doing the same thing. What was your goal
here?
>
> print (i[1:3,])
> }
> }
David Winsemius, MD
Alameda, CA, USA
David Winsemius, MD
Alameda, CA, USA
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